Balancing the Equation for the Combustion of Pentane (C5H12)?

Balancing the Equation for the Combustion of Pentane (C5H12)?

WebMar 2, 2016 · Problems with $\ce{C5H12}$ (A) Given that the volumes were supposed to follow the ideal gas law, 20 $\mathrm{cm}^3$ of hydrocarbon reacts with 150 $\mathrm{cm}^3$ of oxygen. That gives a molar ration of 2 to 15. But the molar ratio of $\ce{C5H12}$ burning is 1 molecule of hydrocarbon to 8 molecules of oxygen, or 2 to 16. WebThis problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. See Answer. Question: If 4.24 mol of C5H12 reacts with excess O2, how many moles of CO2 will be produced by the following combustion reaction? C5H12+8O2 6H2O+5CO2 moles of CO2: If 4.24 mol of C5H12 reacts with … 44 bcs apply process WebMar 20, 2024 · If 4.36 moles of C5H12 reacts with excess O2, how many moles of CO2 will be produced in the following combustion reaction? C5H12 + 8O2 -----> 6H2O + 5CO2 Chemistry http://www.negoce-en-ligne.com/replacement-canopy/c5h12-o2-%3D-co2-%2B-h2o-coefficient best lens company for eyeglasses WebC₅H₁₂ + O₂ --> 5CO₂ + 6H₂O The new tally is: Reactants: C=5, H=12, O=2 Products: C=5, H=12, O=16 So, the coefficient for water is even, as we required. All we have left to do is … WebAnswer (1 of 2): The key to answering this question is having a balanced chemical equation for the reaction. If it is not provided you will have to work it out yourself. Begin by identifying the reactants and products. Assuming complete combustion, the pentane will react with oxygen to produce ... 44 bcs apply last date 2022

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