jz rx jd kx ms v3 98 9f mz lh pa mv 92 vk s8 lj 13 3a 56 l1 7g iz 9s vl 8n f3 ft ke hj ez nh 5q 1y ba wg lg wr a5 5w 6d v2 bk 5g 64 h2 tu s3 jd xn 46 es
7 d
jz rx jd kx ms v3 98 9f mz lh pa mv 92 vk s8 lj 13 3a 56 l1 7g iz 9s vl 8n f3 ft ke hj ez nh 5q 1y ba wg lg wr a5 5w 6d v2 bk 5g 64 h2 tu s3 jd xn 46 es
Weban athlete is given 180g of glucose (c6 h12 o6). he utilises 50% of the energy due to internal combustionin the body. In order to avoid storage of energy oin the body, calculate the mass of water he'll need to perspire. Given enthalpy of combustion of glucose is -2800 kj/mol and enthalipy os evaporation of water is 44kj/mol. WebMar 28, 2024 · Carbs are an athlete's main fuel. Your body changes them to glucose, a form of sugar, and stores it in your muscles as glycogen. When you exercise, your body changes glycogen into energy. If you exercise for under 90 minutes, you have enough glycogen in your muscles, even for high-intensity activities. colored tournament title rocket league WebExpert Answer. For Glucose : Given data , • Mass (m) = 4.0 g • Molecular mass (M) = 180 g/mol Now , Moles of glucose (n) = m/M …. View the full answer. Transcribed image text: are the mole fractions of glucose and water in a solution containing 4.0 g of glucose dissolved in 25.2 g of w Mglucose = 180 g moll and M (H2O) = 18 g mol-. WebBoth glycogen and glucose need to be broken down before they can deliver energy to the muscle. The breakdown of glycogen is easy. That is because glycogen is a chain of glucose molecules, that has multiple places to … dr jeffrey radecki allentown pa WebMar 2, 2024 · Therefore, the energy taken when an athlete consumes the 1 gram of glucose is equalled to\[\text{ 2808 kJ }\]. Hence, (B) is the correct option. Note: Note that, we have to consider the molecules of the glucose. Thus, we are considering that the 1 mole of glucose has $\text{ 180 g }$ of glucose in it. WebAn athlete is given 180 g of glucose (C 6 H 12 O 6) He utilises 50% of the energy due to internal combustion in the body.In order to avoid storage of energy in the body.Calculate the mass of water he would need to perspire.Given enthalpy of combustion of glucose is − 2800 K J m o l − 1 colored traduction WebAn athlete is given 180 g of glucose (C 6H 12O 6) He utilises 50% of the energy due to internal combustion in the body.In order to avoid storage of energy in the body.Calculate …
You can also add your opinion below!
What Girls & Guys Said
WebApr 7, 2024 · Given, Mass of glucose = 180 g. Molar mass of glucose = 180 g/mol. The formula for the calculation of moles is shown below: Thus, Given, Mass of water = 162 g. Molar mass of water = 18 g/mol. The formula for the calculation of moles is shown below: Thus, Applying in the expression for mole fraction as:-Correct answer is:- d. 0.10 WebFeb 27, 2024 · An athlete is given 100 g glucose (C 6 H 12 O 6) of energy equivalent to 1560 kJ. He utilizes 50 percent of this gained energy in the event. In order to avoid storage of … colored townhouse in notting hill london WebMay 8, 2024 · Glucose and fat are essential to powering muscles. But glucose is the only energy source that fuels the brain and sustains motivation to keep going. "Hitting the wall," the common term used … WebJul 9, 2013 · Muscle glycogen, the predominant form of stored glucose in the body, and blood glucose are the main energy substrates for muscle contraction during exercise. Sucrose is an ideal substance for ... dr. jeffrey remington port colborne WebAn athlete takes 100 gm of glucose of energy equivalent to 1560 kJ. How much amount of energy is uptaken by 1 gm molecule of glucose? (1) 15.6 kJ (2) 2808 kJ (3) 1560 kJ (4) … WebMar 29, 2024 · An athlete is given 180 g of glucose ` (C_ (6)H_ (12)O_ (6))`. He utilises 50% of the energy due to internal combustion in the body. In order to avoid storage of … dr jeffrey rico morgantown wv WebJun 8, 2024 · An athlete is given 180 \mathrm{~g} of glucose \left(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\ri. The world’s only live instant tutoring platform. About …
WebAn athlete is given 180 g of glucose (C 6 H 12 O 6) He utilises 50% of the energy due to internal combustion in the body.In order to avoid storage of energy in the body.Calculate … dr jeffrey rapaport prp reviews Weban athlete is given 180 g of glucose. he utilises 50% of the energy due to internal combustion in the body. in order to avoid storage of energy in the body, calculate the … WebThe total time spent in a stretching routine hardly ever exceeds 5 minutes. Even in athletics, stretching is given minor importance in the overall training program. An athlete might spend just a little more time stretching than the average person, usually because stretching is part of a warm-up routine. dr jeffrey reisman morristown new jersey WebAn athlete is given 180 g of glucose (C H2O2). He utilises 50% of the energy due to internal combustion in the body. In order to avoid storage of energy in the body, calculate the mass of water he would need to perspire. Given enthalpy of combustion of glucose is -2800 kJ mot and enthalpy of evaporation of water is 44 kJ mol-1. 23. WebMar 9, 2024 · Hint: Using the molar mass of the glucose we will get the energy that is actually consumed by the glucose. The enthalpy of evaporation of water is given and … colored tp WebDec 17, 2024 · Optimal levels of glucose = optimal levels of performance. The energy generated from carbohydrates is available much faster than that from fat. It’s no question – in both scientific and athletic communities – …
Weban athlete is given 180 g of glucose. he utilises 50% of the energy due to internal combustion in the body. in order to avoid storage of energy in the body, calculate the mass of water he would need to perspire. given enthalpy of combustion of glucose is -2800 kj/mol and enthalpy of evaporation of water is 44 kj / mol. dr. jeffrey rother ardmore oklahoma WebMar 28, 2024 · Carbs are an athlete's main fuel. Your body changes them to glucose, a form of sugar, and stores it in your muscles as glycogen. When you exercise, your body … dr jeffrey reisman morristown