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How do you find the domain and range of #x + sqrt( x-1 )?

How do you find the domain and range of #x + sqrt( x-1 )?

WebThe cube root of a number a a, denoted as \sqrt [3] {a}, 3 a, is the number b b such that b^3=a. b3 = a. The cube root symbol acts similarly to the square root symbol. It is often called a radical, and the number or expression underneath the top line of the symbol is called the radicand. WebAug 26, 2015 · The range of the function will be determined by the fact that the square root of a real number must always be positive. The smallest value the function can take will happen for x = − 1 and for x = 1, since those values of x will make the radical term equal to zero. √( −1)2 − 1 = 0 and √(1)2 − 1 = 0. The range of the function will ... ad image facebook WebIn general, the cube roots of r e i θ are given by r 1 / 3 e i θ / 3, r 1 / 3 e i ( θ / 3 + 2 π / 3) and r 1 / 3 e i ( θ / 3 + 4 π / 3). In your case r = 1 and θ = π, so your cube roots are e i π / 3, e i π, and e i 5 π / 3. Put back into rectangular form, they are 1 2 + i 3 2, − 1, and 1 2 − i 3 2. Share Cite Follow answered Nov 3, 2010 at 14:44 ad images inc WebMay 27, 2024 · Explanation: Since a square root cannot have a negative under the radical (or else it would be imaginary), x ≥ 1. When x = 1, the range (or y) is (1) + √1 − 1 = 1. Thus, the range of y is y ≥ 1. Thus, in interval notation, the domain of the function is [1,∞), and the range is [1,∞) Answer link. WebJan 30, 2024 · How to Find the Domain of a Cube Root Function Using Interval Notation: f (x) = (1 - 2x)^ (1/3) The Glaser Tutoring Company 36.4K subscribers Subscribe 12K … a dilute acidic aqueous solution of na2so4 is electrolyzed WebAlgebra. Find the Domain and Range y = square root of x+1. y = √x + 1 y = x + 1. Set the radicand in √x x greater than or equal to 0 0 to find where the expression is defined. x ≥ 0 x ≥ 0. The domain is all values of x x that make the expression defined. Interval Notation:

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