In an ap the sum of first ten terms is - 150
WebThe sum of the first five terms of an AP and the sum of the first seven terms of the same AP is 167. If the sum of the first ten terms of this AP is 235, find the sum of its first twenty … WebMar 27, 2024 · Solution For 10] Find the sum of first ' n ' terms of an AP 2 ,8 ,18 ,32 , 11] If α,β and γ are the zeroes of the polynomial P(x)=x3−6x2−x+30 then fin. The world’s only live instant tutoring platform. Become a tutor About us Student login Tutor login. Login. Student Tutor. Filo instant Ask button for chrome browser. ...
In an ap the sum of first ten terms is - 150
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WebThe sum of the first five terms of an AP and the sum of the first seven terms of the same AP is 167. If the sum of the first ten terms of this AP is 235, find the sum of its first twenty terms. Solution: Given, the sum of the first five terms of an AP and the sum of the first seven terms of the same AP is 167. WebThe sum of the first five terms of an AP and the sum of the first seven terms of the same AP is 167. If the sum of the first ten terms of this AP is 235, find the sum of its first twenty terms. Q.
WebLe a1, a2, ..., a10 are terms of an A.P given S10 = a1+a2+...+10 = 150 But we know that: s10 = (a1+a10)*10/2 = 150 ==> a1+a10 = 150/5 ==> a1+a10 = 30 ==> a10 = 30 - a1...... (1) But a10... WebApr 8, 2024 · Given sum of first ten terms = − 150. We know that Sum of n terms of AP S n = n 2 [ 2 a + ( n − 1) d] Therefore, ⇒ S 10 = 10 2 [ 2 a + ( 10 − 1) d] ⇒ − 150 = 5 [ 2 a + 9 d] ⇒ …
WebMay 14, 2024 · Given: Sum of first ten terms that is, S 10 = -150 and Sum of next ten terms is -550. To find: The A.P. Solution: Let, first term = a Last term = a n We know in an A.P, a n = a + (n – 1) d. For n = 10. a n = a + (10 - 1)d. a n = a + 9d. We know, sum of n terms. s n = \(\frac{n}{2}[a + l]\). l and a n means the last term.. Put the value of l in (1),So, S 10 = … WebJun 24, 2024 · The AP is 3, - 1,- 5 ,- 9,…... Step-by-step explanation: Given : S10 = - 150 and sum of its next 10 terms is - 550. By using the formula ,Sum of nth terms , Sn = n/2 [2a + (n – 1) d] S10 = (10/2) [ 2a + (10 - 1)d ] -150 = 10/2 [2a + 9d] -150 = 5 [2a + 9d] -150/5 = 2a + 9d - 30 = 2a + 9d 2a + 9d = - 30 ………... (1) And
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WebSum In an A.P., the sum of first ten terms is −150 and the sum of its next ten terms is −550. Find the A.P. Advertisement Remove all ads Solution Here, we are given S 10 = -150 and sum of the next ten terms is −550. Let us take the first term of the A.P. as a and the common difference as d. So, let us first find a10. shuttle service to snaWebS n = n/2 {2a + (n − 1)d} Given that sum of the first 10 terms of an A.P. is -150. S 10 = -150 And the sum of next 10 terms is -550. So, the sum of first 20 terms = Sum of first 10 … shuttle service to tpaWebFor an AP, the sum of the first n terms can be calculated if the first term, common difference and the total terms are known. The formula for the arithmetic progression sum is explained below: Consider an AP … the park highlanderWebThe sum of first 10 terms of an AP is -150 and the sum of its next 10 terms is -550. Find the AP. Solution Let a be the first term and d be the common difference of the AP. Then, It is … the park hermitage tnWebClick here👆to get an answer to your question ️ In an A.P. the sum of first ten terms is \( - 150 \) and the sum of its next ten terms is - Find the A.P CBSE 2010 Sum of the first 14 terms of an A.P. is 1505 and its first term is \( 10 . \) Find its \( 25 ^ { \text { th } } \) term the park hillside athensWebHere, we are given S 10 = - 150 and sum of the next ten terms is - 550. Let us take the first term of the A.P. as a and the common difference as d. So, let us first find a 10. First term = a. Last term = a 10. As, a n = a + ( n - 1) d. For the 10 th term, a 10 = a + ( 10 - 1) d. = a + 9 d. So, here we can find the sum of the n terms of the ... the park hillside portalWebAnswer to 11. Use the sum of the first ten terms to approximate the park highland falls